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4.9x^2-3x=220
We move all terms to the left:
4.9x^2-3x-(220)=0
a = 4.9; b = -3; c = -220;
Δ = b2-4ac
Δ = -32-4·4.9·(-220)
Δ = 4321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{4321}}{2*4.9}=\frac{3-\sqrt{4321}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{4321}}{2*4.9}=\frac{3+\sqrt{4321}}{9.8} $
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